The Official Homework Help Thread

Is someone here able to help me with my german stuff? I find it very hard, but fun at the same time!
 
Ok, so I need help with a math problem. Here it is (sorry for the big picture and all even though it's just one problem, I didn't know how to type the exponents)

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Can someone help me with this problem? Thanks!
 
Need help:
A baseball team played 156 complete games last season. They had 24 fewer wins than losses. How many games did the team win? (66?)

A high school graduating class is made up of 406 students. There are 154 more girls than boys. How many boys are in the class?

A biologist collected 230 fern and moss samples. There were 110 fewer ferns than moss samples. How many fern samples did the biologist collect?

An employee earned $15,820 this year. This was a raise of 14% over last year. What was his salary last year?
Round to the nearest dollar, if necessary. (I got $13,605. Correct?)
 
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Need help:

A high school graduating class is made up of 406 students. There are 154 more girls than boys. How many boys are in the class?

49 more girls?

- - - Post Merge - - -

I really have no clue,btw

It's a system of equations.

Let's assume X = Boys and Y = Girls

X + Y = 406
(Boys + Girls = Total)
Y = X + 154 (154 more girls than boys)

Since the 2nd Equation gives us a value for Y in terms of X, we can use it to replace X in the first equation

X + (X + 154) = 406


Now you just work out the equation.

2X = 252
X = 126


There are 126 Boys.
 
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It's a system of equations.

Let's assume X = Boys and Y = Girls

X + Y = 406
(Boys + Girls = Total)
Y = X + 154 (154 more girls than boys)

Since the 2nd Equation gives us a value for Y in terms of X, we can use it to replace X in the first equation

X + (X + 154) = 406


Now you just work out the equation.

2X = 252
X = 126


There are 126 Boys.
Thank you!
 
How do you get the number of valence electrons an element has? Also how do you do chemical formulas for ionic compounds? I am terrible at science
 
Can someone tell me how I do Slope and Similar Triangles?

You'd need the coordinates. Then use the formula for slopes which you should know, plug the coordinates in and you get the slope.

There's a ton a ways of finding similar triangles, is there a certain way you need to solve it?
 
Can someone tell me how I do Slope and Similar Triangles?

the formula for slope is (y1-y2)/(x1-x2), and im assuming this is what you're asking for. if it is and you're having trouble following the formula, think of it as swapping the x and y values on each side and moving x1/x2 up and over to the left on top of y1 and y2. just as an example, let's say you got (4, -3) (7, 3). swap x and y on both sides so it's (-3, 4) (3, 7). it should look something like this on paper;

3 , 7
--------
-3 , 4

subtract from the top to bottom and you should get 6/3. simplify that and you get 2 as your answer for the slope. im hoping this is what you were asking for and that i did this all correctly x'D. if you need to know how to find the slope on a graph, divide the rise by the run
 
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How do you get the number of valence electrons an element has? Also how do you do chemical formulas for ionic compounds? I am terrible at science

You can tell an element's valence electrons based on where it is on the periodic table. It's group number tells you how many valence electrons it has. A group is a column in the periodic table-so, for example, Nitrogen is in group 5A, so it has 5 Valence electrons. It would want to bond with some atom(s) that make it have 8 Valence electrons, like something from group 3A.

For ionic compounds, it will always be a metal and a nonmetal, where the metal goes first in the name. E.g., Lithium Oxide= Li₂O
When making formulas for ionic compounds, you look at all of the element's charges. Lithium's charge is +1, Oxygen's is 2-; To make the formula, you cross over each element's charge to the subscript of (under) the other, so Li+1 and O+2 ---> Li₂O. You don't need to put the 1 under Oxygen.

Sorry I'm not the best at explaining it :( I wish I had a pic to show you! Good luck ^^
 
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