This was my long-form work for Egg 8 after @FraudulentDimetrodon helped get me unstuck.Does someone mind sharing the math behind egg 8? I didn't even try it because I can't math and even seeing the answer now I'm like, idk man I would like to educate myself though!
(this was to turn the eggs into variables I could more easily manipulate)
Operators: (reasonably, only plus/minus/multiply can be used)
Ruby = minus (-)
Hopkins = multiply (*)
Cole = plus (+)
Main reasoning is the second equation, d must be a single digit number, and dd a double digit of the same number, which is only able to be obtained by multiplying d by 11 (thus we get d * (b + a) = dd, leaving Ruby as minus by default).
(edited in since I realized I didn't explain this, lol: ) Coco is not a normal operator, but works by inverting the eggs, hence why I've labeled her as "I". Note that this is actually the normal definition for "invert" (i.e. "put upside down"), not the mathematical definition of inversion!
ai = ?
a = ?
b = ?
c = ?
d = ?
e = ?
a - b = c
d * (b + a) = dd -> b + a = 11
e - b = d + c
I(cae) = e(ai)c
I(e*d) + a - e = ??
a must be either 6 or 9 (only numbers that can invert into one another)
c, d, e must be either 0, 1, 2, 5 or 8 (only numbers which can invert into themselves)
b + a, pairs can only be 2 + 9 or 5 + 6. But when trying 9 - 2, c cannot be 7, so we must have a = 6, b = 5, c = 1
We then have e - 5 = d + 1, or e = d + 6. We know d/e must be 0, 2 or 8, and only 2 and 8 make sense, so e = 8, d = 2 to complete that equation.
Inverting a gives us ai = 9.
Therefore, the answer is:
ai = 9
a = 6
b = 5
c = 1
d = 2
e = 8
I(e*d) + a - e = ??
I(8*2) + 6 - 8 = ??
I(16) - 2 = ??
91 - 2 = ??
?? = 89
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